3242.设计相邻元素求和服务

链接：3242.设计相邻元素求和服务
难度：Easy
标签：设计、数组、哈希表、矩阵、模拟
简介：给你一个 n x n 的二维数组 grid，它包含范围 [0, n2 - 1] 内的不重复元素。实现 neighborSum 类。

题解 1 - undefined

• 编辑时间：2024-11-09
• 执行用时：28ms
• 内存消耗：16.89MB
• 编程语言：undefined
• 解法介绍：遍历

dirs1 = [(0, 1), (1, 0), (0, -1), (-1, 0)]
dirs2 = [(1, 1), (1, -1), (-1, 1), (-1, -1)]
class NeighborSum:
    def __init__(self, grid: List[List[int]]):
        self.grid = grid
        self.n = len(grid)
        self.m = len(grid[0])
        self.map = {grid[i][j]: (i, j) for i in range(self.n) for j in range(self.m)}
    def get(self, value: int, dirs: List[int]) -> int:
        i, j = self.map[value]
        res = 0
        for dir in dirs:
            ni = i + dir[0]
            nj = j + dir[1]
            if 0 <= ni < self.n and 0 <= nj < self.m:
                res += self.grid[ni][nj]
        return res
    def adjacentSum(self, value: int) -> int:
        return self.get(value, dirs1)
    def diagonalSum(self, value: int) -> int:
        return self.get(value, dirs2)